Fail gracefully on bad stack
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63ce394892
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@ -13,4 +13,4 @@
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# You should have received a copy of the GNU Affero General Public License
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# along with this program. If not, see <http:#www.gnu.org/licenses/>.
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stack_file_name = "stack.yml"
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stack_file_name = "stack.yml"
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@ -26,7 +26,7 @@ import importlib.resources
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from pathlib import Path
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import yaml
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from stack_orchestrator.constants import stack_file_name
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from stack_orchestrator.util import include_exclude_check
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from stack_orchestrator.util import include_exclude_check, error_exit
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class GitProgress(git.RemoteProgress):
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@ -245,6 +245,8 @@ def command(ctx, include, exclude, git_ssh, check_only, pull, branches, branches
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# In order to be compatible with Python 3.8 we need to use this hack to get the path:
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# See: https://stackoverflow.com/questions/25389095/python-get-path-of-root-project-structure
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stack_file_path = Path(__file__).absolute().parent.parent.joinpath("data", "stacks", stack, stack_file_name)
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if not stack_file_path.exists():
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error_exit(f"stack {stack} does not exist")
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with stack_file_path:
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stack_config = yaml.safe_load(open(stack_file_path, "r"))
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# TODO: syntax check the input here
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@ -167,3 +167,8 @@ def global_options(ctx):
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# TODO: hack
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def global_options2(ctx):
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return ctx.parent.obj
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def error_exit(s):
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print(f"ERROR: {s}")
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sys.exit(1)
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