Check stack is a path
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16
stack_orchestrator/constants.py
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16
stack_orchestrator/constants.py
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# Copyright © 2023 Vulcanize
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# This program is free software: you can redistribute it and/or modify
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# it under the terms of the GNU Affero General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU Affero General Public License for more details.
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# You should have received a copy of the GNU Affero General Public License
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# along with this program. If not, see <http:#www.gnu.org/licenses/>.
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stack_file_name = "stack.yml"
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@ -25,6 +25,7 @@ import click
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import importlib.resources
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from pathlib import Path
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import yaml
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from stack_orchestrator.constants import stack_file_name
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from stack_orchestrator.util import include_exclude_check
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@ -238,9 +239,12 @@ def command(ctx, include, exclude, git_ssh, check_only, pull, branches, branches
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repos_in_scope = []
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if stack:
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# In order to be compatible with Python 3.8 we need to use this hack to get the path:
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# See: https://stackoverflow.com/questions/25389095/python-get-path-of-root-project-structure
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stack_file_path = Path(__file__).absolute().parent.parent.joinpath("data", "stacks", stack, "stack.yml")
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# Check if the stack argument is a path or a plain string.
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stack_file_path = Path(stack).joinpath(stack_file_name)
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if not stack_file_path.exists():
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# In order to be compatible with Python 3.8 we need to use this hack to get the path:
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# See: https://stackoverflow.com/questions/25389095/python-get-path-of-root-project-structure
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stack_file_path = Path(__file__).absolute().parent.parent.joinpath("data", "stacks", stack, stack_file_name)
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with stack_file_path:
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stack_config = yaml.safe_load(open(stack_file_path, "r"))
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# TODO: syntax check the input here
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