2019-01-09 11:48:36 +00:00
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.. index:: ! type;conversion, ! cast
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.. _types-conversion-elementary-types:
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Conversions between Elementary Types
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====================================
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Implicit Conversions
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--------------------
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2019-12-16 15:35:53 +00:00
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An implicit type conversion is automatically applied by the compiler in some cases
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during assignments, when passing arguments to functions and when applying operators.
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2019-06-24 10:40:16 +00:00
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In general, an implicit conversion between value-types is possible if it makes
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sense semantically and no information is lost.
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For example, ``uint8`` is convertible to
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``uint16`` and ``int128`` to ``int256``, but ``int8`` is not convertible to ``uint256``,
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because ``uint256`` cannot hold values such as ``-1``.
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2019-01-09 11:48:36 +00:00
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2019-12-16 15:35:53 +00:00
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If an operator is applied to different types, the compiler tries to implicitly
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convert one of the operands to the type of the other (the same is true for assignments).
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This means that operations are always performed in the type of one of the operands.
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For more details about which implicit conversions are possible,
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please consult the sections about the types themselves.
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In the example below, ``y`` and ``z``, the operands of the addition,
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do not have the same type, but ``uint8`` can
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be implicitly converted to ``uint16`` and not vice-versa. Because of that,
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``y`` is converted to the type of ``z`` before the addition is performed
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2021-02-03 22:00:04 +00:00
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in the ``uint16`` type. The resulting type of the expression ``y + z`` is ``uint16``.
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2019-12-16 15:35:53 +00:00
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Because it is assigned to a variable of type ``uint32`` another implicit conversion
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is performed after the addition.
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2021-06-25 10:25:29 +00:00
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.. code-block:: solidity
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2019-12-16 15:35:53 +00:00
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uint8 y;
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uint16 z;
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uint32 x = y + z;
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2019-01-09 11:48:36 +00:00
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Explicit Conversions
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--------------------
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2019-06-24 10:40:16 +00:00
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If the compiler does not allow implicit conversion but you are confident a conversion will work,
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an explicit type conversion is sometimes possible. This may
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result in unexpected behaviour and allows you to bypass some security
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2019-01-09 11:48:36 +00:00
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features of the compiler, so be sure to test that the
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result is what you want and expect!
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Take the following example that converts a negative ``int`` to a ``uint``:
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2019-01-09 11:48:36 +00:00
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2021-06-25 10:25:29 +00:00
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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2019-04-30 14:46:43 +00:00
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int y = -3;
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2019-01-09 11:48:36 +00:00
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uint x = uint(y);
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At the end of this code snippet, ``x`` will have the value ``0xfffff..fd`` (64 hex
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characters), which is -3 in the two's complement representation of 256 bits.
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If an integer is explicitly converted to a smaller type, higher-order bits are
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cut off:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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uint32 a = 0x12345678;
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uint16 b = uint16(a); // b will be 0x5678 now
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2019-06-24 10:40:16 +00:00
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If an integer is explicitly converted to a larger type, it is padded on the left (i.e., at the higher order end).
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The result of the conversion will compare equal to the original integer:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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uint16 a = 0x1234;
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uint32 b = uint32(a); // b will be 0x00001234 now
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assert(a == b);
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Fixed-size bytes types behave differently during conversions. They can be thought of as
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sequences of individual bytes and converting to a smaller type will cut off the
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sequence:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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bytes2 a = 0x1234;
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bytes1 b = bytes1(a); // b will be 0x12
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If a fixed-size bytes type is explicitly converted to a larger type, it is padded on
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the right. Accessing the byte at a fixed index will result in the same value before and
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after the conversion (if the index is still in range):
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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bytes2 a = 0x1234;
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bytes4 b = bytes4(a); // b will be 0x12340000
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assert(a[0] == b[0]);
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assert(a[1] == b[1]);
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Since integers and fixed-size byte arrays behave differently when truncating or
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padding, explicit conversions between integers and fixed-size byte arrays are only allowed,
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if both have the same size. If you want to convert between integers and fixed-size byte arrays of
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different size, you have to use intermediate conversions that make the desired truncation and padding
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rules explicit:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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bytes2 a = 0x1234;
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uint32 b = uint16(a); // b will be 0x00001234
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uint32 c = uint32(bytes4(a)); // c will be 0x12340000
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uint8 d = uint8(uint16(a)); // d will be 0x34
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uint8 e = uint8(bytes1(a)); // e will be 0x12
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2021-04-13 07:07:23 +00:00
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``bytes`` arrays and ``bytes`` calldata slices can be converted explicitly to fixed bytes types (``bytes1``/.../``bytes32``).
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In case the array is longer than the target fixed bytes type, truncation at the end will happen.
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If the array is shorter than the target type, it will be padded with zeros at the end.
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2021-06-25 10:25:29 +00:00
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.. code-block:: solidity
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2021-04-13 07:07:23 +00:00
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// SPDX-License-Identifier: GPL-3.0
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pragma solidity ^0.8.5;
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contract C {
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bytes s = "abcdefgh";
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function f(bytes calldata c, bytes memory m) public view returns (bytes16, bytes3) {
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require(c.length == 16, "");
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bytes16 b = bytes16(m); // if length of m is greater than 16, truncation will happen
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b = bytes16(s); // padded on the right, so result is "abcdefgh\0\0\0\0\0\0\0\0"
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bytes3 b1 = bytes3(s); // truncated, b1 equals to "abc"
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b = bytes16(c[:8]); // also padded with zeros
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return (b, b1);
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}
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}
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2019-01-09 11:48:36 +00:00
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.. _types-conversion-literals:
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Conversions between Literals and Elementary Types
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=================================================
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Integer Types
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-------------
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Decimal and hexadecimal number literals can be implicitly converted to any integer type
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that is large enough to represent it without truncation:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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uint8 a = 12; // fine
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uint32 b = 1234; // fine
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uint16 c = 0x123456; // fails, since it would have to truncate to 0x3456
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2020-10-26 10:01:18 +00:00
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.. note::
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Prior to version 0.8.0, any decimal or hexadecimal number literals could be explicitly
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converted to an integer type. From 0.8.0, such explicit conversions are as strict as implicit
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conversions, i.e., they are only allowed if the literal fits in the resulting range.
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2019-01-09 11:48:36 +00:00
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Fixed-Size Byte Arrays
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----------------------
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Decimal number literals cannot be implicitly converted to fixed-size byte arrays. Hexadecimal
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number literals can be, but only if the number of hex digits exactly fits the size of the bytes
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type. As an exception both decimal and hexadecimal literals which have a value of zero can be
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converted to any fixed-size bytes type:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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bytes2 a = 54321; // not allowed
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bytes2 b = 0x12; // not allowed
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bytes2 c = 0x123; // not allowed
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bytes2 d = 0x1234; // fine
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bytes2 e = 0x0012; // fine
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bytes4 f = 0; // fine
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bytes4 g = 0x0; // fine
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String literals and hex string literals can be implicitly converted to fixed-size byte arrays,
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if their number of characters matches the size of the bytes type:
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.. code-block:: solidity
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2019-01-09 11:48:36 +00:00
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bytes2 a = hex"1234"; // fine
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bytes2 b = "xy"; // fine
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bytes2 c = hex"12"; // not allowed
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bytes2 d = hex"123"; // not allowed
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bytes2 e = "x"; // not allowed
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bytes2 f = "xyz"; // not allowed
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Addresses
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---------
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As described in :ref:`address_literals`, hex literals of the correct size that pass the checksum
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test are of ``address`` type. No other literals can be implicitly converted to the ``address`` type.
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Explicit conversions from ``bytes20`` or any integer type to ``address`` result in ``address payable``.
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2019-09-04 15:45:12 +00:00
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An ``address a`` can be converted to ``address payable`` via ``payable(a)``.
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