rpc: linear time batch response matching (#23856)

This avoids quadratic time complexity in the lookup of the batch element
corresponding to an RPC response. Unfortunately, the new approach
requires additional memory for the mapping from ID to index.

Fixes #22805
This commit is contained in:
Felix Lange 2021-11-04 17:44:35 +01:00 committed by GitHub
parent 03bc8b7858
commit 53b94f135a
No known key found for this signature in database
GPG Key ID: 4AEE18F83AFDEB23

View File

@ -17,7 +17,6 @@
package rpc package rpc
import ( import (
"bytes"
"context" "context"
"encoding/json" "encoding/json"
"errors" "errors"
@ -360,7 +359,10 @@ func (c *Client) BatchCall(b []BatchElem) error {
// //
// Note that batch calls may not be executed atomically on the server side. // Note that batch calls may not be executed atomically on the server side.
func (c *Client) BatchCallContext(ctx context.Context, b []BatchElem) error { func (c *Client) BatchCallContext(ctx context.Context, b []BatchElem) error {
msgs := make([]*jsonrpcMessage, len(b)) var (
msgs = make([]*jsonrpcMessage, len(b))
byID = make(map[string]int, len(b))
)
op := &requestOp{ op := &requestOp{
ids: make([]json.RawMessage, len(b)), ids: make([]json.RawMessage, len(b)),
resp: make(chan *jsonrpcMessage, len(b)), resp: make(chan *jsonrpcMessage, len(b)),
@ -372,6 +374,7 @@ func (c *Client) BatchCallContext(ctx context.Context, b []BatchElem) error {
} }
msgs[i] = msg msgs[i] = msg
op.ids[i] = msg.ID op.ids[i] = msg.ID
byID[string(msg.ID)] = i
} }
var err error var err error
@ -391,13 +394,7 @@ func (c *Client) BatchCallContext(ctx context.Context, b []BatchElem) error {
// Find the element corresponding to this response. // Find the element corresponding to this response.
// The element is guaranteed to be present because dispatch // The element is guaranteed to be present because dispatch
// only sends valid IDs to our channel. // only sends valid IDs to our channel.
var elem *BatchElem elem := &b[byID[string(resp.ID)]]
for i := range msgs {
if bytes.Equal(msgs[i].ID, resp.ID) {
elem = &b[i]
break
}
}
if resp.Error != nil { if resp.Error != nil {
elem.Error = resp.Error elem.Error = resp.Error
continue continue