cerc-io/stack-orchestrator
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Support external stack file #650

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telackey merged 7 commits from dboreham/external-stack-file into main 2023-11-15 03:59:48 +00:00
Conversation 0 Commits 7 Files Changed 5 +23 -3
2 changed files with 23 additions and 3 deletions
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16
stack_orchestrator/constants.py Normal file
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@ -0,0 +1,16 @@
# Copyright © 2023 Vulcanize
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU Affero General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Affero General Public License for more details.
# You should have received a copy of the GNU Affero General Public License
# along with this program. If not, see <http:#www.gnu.org/licenses/>.
stack_file_name = "stack.yml"

10
stack_orchestrator/repos/setup_repositories.py
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@ -25,6 +25,7 @@ import click
import importlib.resources
from pathlib import Path
import yaml
from stack_orchestrator.constants import stack_file_name
from stack_orchestrator.util import include_exclude_check
@ -238,9 +239,12 @@ def command(ctx, include, exclude, git_ssh, check_only, pull, branches, branches
repos_in_scope = []
if stack:
# In order to be compatible with Python 3.8 we need to use this hack to get the path:
# See: https://stackoverflow.com/questions/25389095/python-get-path-of-root-project-structure
stack_file_path = Path(__file__).absolute().parent.parent.joinpath("data", "stacks", stack, "stack.yml")
# Check if the stack argument is a path or a plain string.
stack_file_path = Path(stack).joinpath(stack_file_name)
if not stack_file_path.exists():
# In order to be compatible with Python 3.8 we need to use this hack to get the path:
# See: https://stackoverflow.com/questions/25389095/python-get-path-of-root-project-structure
stack_file_path = Path(__file__).absolute().parent.parent.joinpath("data", "stacks", stack, stack_file_name)
with stack_file_path:
stack_config = yaml.safe_load(open(stack_file_path, "r"))
# TODO: syntax check the input here