Restrict fork choice iterators to the root
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6bb3a65189
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@ -470,6 +470,7 @@ where
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// descendant of both `node` and `prev_in_tree`.
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if self
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.iter_ancestors(child_hash)?
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.take_while(|(_, slot)| *slot >= self.root_slot())
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.any(|(ancestor, _slot)| ancestor == node.block_hash)
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{
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let child = self.get_mut_node(child_hash)?;
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@ -555,6 +556,7 @@ where
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fn find_prev_in_tree(&mut self, hash: Hash256) -> Option<Hash256> {
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self.iter_ancestors(hash)
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.ok()?
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.take_while(|(_, slot)| *slot >= self.root_slot())
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.find(|(root, _slot)| self.nodes.contains_key(root))
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.and_then(|(root, _slot)| Some(root))
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}
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@ -562,8 +564,12 @@ where
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/// For the two given block roots (`a_root` and `b_root`), find the first block they share in
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/// the tree. Viz, find the block that these two distinct blocks forked from.
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fn find_highest_common_ancestor(&self, a_root: Hash256, b_root: Hash256) -> Result<Hash256> {
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let mut a_iter = self.iter_ancestors(a_root)?;
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let mut b_iter = self.iter_ancestors(b_root)?;
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let mut a_iter = self
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.iter_ancestors(a_root)?
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.take_while(|(_, slot)| *slot >= self.root_slot());
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let mut b_iter = self
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.iter_ancestors(b_root)?
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.take_while(|(_, slot)| *slot >= self.root_slot());
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// Combines the `next()` fns on the `a_iter` and `b_iter` and returns the roots of two
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// blocks at the same slot, or `None` if we have gone past genesis or the root of this tree.
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